x^2=9/400

Solution for x^2=9/400 equation:

x^2=9/400

We move all terms to the left:

x^2-(9/400)=0

We add all the numbers together, and all the variables

x^2-(+9/400)=0

We get rid of parentheses

x^2-9/400=0

We multiply all the terms by the denominator


x^2*400-9=0

Wy multiply elements

400x^2-9=0

a = 400; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·400·(-9)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*400}=\frac{-120}{800}
=-3/20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*400}=\frac{120}{800}
=3/20
$